Respuesta :

moles CO = 10 g x 1mol 28g = 0.357 moles in 3 L = 0.119 mol/L at STP 
P1/n1 = P2/n2 
101.325 kPa/0.119 = 200 kPa/n2 
n2 = 0.235 moles/L = 0.235mol x 28g/mol = 6.6g/L (assuming no change in temp) 

Answer : The solubility of carbon monoxide gas at pressure 200 kPa is, 6.579 g/L

Explanation :

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

[tex]S\propto P[/tex]

or,

[tex]\frac{S_1}{S_2}=\frac{P_1}{P_2}[/tex]

where,

[tex]S_1[/tex] = initial solubility of gas = [tex]\frac{10g}{3L}[/tex]

[tex]S_2[/tex] = final solubility of gas = ?

[tex]P_1[/tex] = initial pressure of gas = 101.325 kPa (at STP)

[tex]P_2[/tex] = final pressure of gas = 200 kPa

Now put all the given values in the above formula, we get the final solubility of the gas.

[tex]\frac{\frac{10g}{3L}}{S_2}=\frac{101.325kPa}{200kPa}[/tex]

[tex]S_2=6.579g/L[/tex]

Therefore, the solubility of carbon monoxide gas at pressure 200 kPa is, 6.579 g/L