Answer:
1. 2.64 kJ 2. 50 W 3. 2.5 A
Explanation:
1. Energy transformed in the lamp, E = IVt where I = current = 0.22 A, V = voltage = 120 V and t = time = 100s
E = 0.22 A × 120 V × 100 s
= 2640 J
= 2.64 kJ
2. The rate at which energy is trans ferred to the resistor is the power.
Power, P = IV where I = current = 5.0 A and V = voltage = 10 V
P = 5.0 A × 10 V = 50 W
3. Since Power P = IV
Current through the heater I = P/V P = 30 W and V = 12 V
I = 30 W/12 V
= 2.5 A
