Answer:
The required sample size increases.
Step-by-step explanation:
The margin of error of a confidence interval is given by:
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which z is related to the confidence level(the higher the confidence level the higher z), [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this question:
The confidence level decreases, so z decreases.
For the margin of error to stay the same, the sample size also has to decrease.
The required sample size increases.
