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You measure 27 watermelons' weights, and find they have a mean weight of 71 ounces. Assume the population standard deviation is 2.8 ounces. Based on this, construct a 95% confidence interval for the true population mean watermelon weight.

Respuesta :

Answer:

(69.94, 72.06)

Step-by-step explanation:

Confidence Interval formula = Mean ± z × Standard deviation/√n

Mean = 71 ounces

Standard deviation = 2.8 ounces

z score = 95% confidence interval = 1.96

Confidence Interval = 71 ± 1.96 × 2.8/√27

= 71 ± 1.96 × 0.5388602512

= 71 ± 1.0561660924

71 - 1.0561660924

= 69.943833908 ounces

Approximately = 69.94 ounces

71 + 1.0561660924

= 72.0561660924 ounces

Approximately = 72.06 ounces

95% Confidence Interval = (69.94, 72.06).

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