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  • 04-05-2018
  • Mathematics
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Where is the second derivative of y = 4xex equal to 0?

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jdoe0001 jdoe0001
  • 04-05-2018
[tex]\bf y=4xe^x\implies \cfrac{dy}{dx}=4e^x+4xe^x\implies \cfrac{d^2y}{dx^2}=8e^x+4xe^x \\\\\\ 0=8e^x+4xe^x\implies 0=4e^x(2+x)\implies 0=2+x\implies -2=x[/tex]
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